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138710753 is a prime number
BaseRepresentation
bin10000100010010…
…00111011100001
3100200000020101022
420101020323201
5241002221003
621433015225
73303010346
oct1021107341
9320006338
10138710753
1171331495
123a554515
132297858c
14145ca7cd
15c29e738
hex8448ee1

138710753 has 2 divisors, whose sum is σ = 138710754. Its totient is φ = 138710752.

The previous prime is 138710729. The next prime is 138710809. The reversal of 138710753 is 357017831.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 136702864 + 2007889 = 11692^2 + 1417^2 .

It is a cyclic number.

It is not a de Polignac number, because 138710753 - 210 = 138709729 is a prime.

It is a super-3 number, since 3×1387107533 (a number of 25 digits) contains 333 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (138710713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69355376 + 69355377.

It is an arithmetic number, because the mean of its divisors is an integer number (69355377).

Almost surely, 2138710753 is an apocalyptic number.

It is an amenable number.

138710753 is a deficient number, since it is larger than the sum of its proper divisors (1).

138710753 is an equidigital number, since it uses as much as digits as its factorization.

138710753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17640, while the sum is 35.

The square root of 138710753 is about 11777.5529291954. The cubic root of 138710753 is about 517.6505857524.

The spelling of 138710753 in words is "one hundred thirty-eight million, seven hundred ten thousand, seven hundred fifty-three".