Base | Representation |
---|---|
bin | 11001110101101111… |
… | …10111111110111111 |
3 | 1022210210210111112222 |
4 | 30322313313332333 |
5 | 211402343041042 |
6 | 10212322315555 |
7 | 1000530250364 |
oct | 147267677677 |
9 | 38723714488 |
10 | 13872627647 |
11 | 597981152a |
12 | 2831ab8bbb |
13 | 1401103418 |
14 | 9585dc46b |
15 | 562d732d2 |
hex | 33adf7fbf |
13872627647 has 4 divisors (see below), whose sum is σ = 13874580720. Its totient is φ = 13870674576.
The previous prime is 13872627641. The next prime is 13872627673. The reversal of 13872627647 is 74672627831.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13872627647 - 222 = 13868433343 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13872627641) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 965843 + ... + 980100.
It is an arithmetic number, because the mean of its divisors is an integer number (3468645180).
Almost surely, 213872627647 is an apocalyptic number.
13872627647 is a deficient number, since it is larger than the sum of its proper divisors (1953073).
13872627647 is an equidigital number, since it uses as much as digits as its factorization.
13872627647 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1953072.
The product of its digits is 4741632, while the sum is 53.
The spelling of 13872627647 in words is "thirteen billion, eight hundred seventy-two million, six hundred twenty-seven thousand, six hundred forty-seven".
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