Base | Representation |
---|---|
bin | 1000000101000010010… |
… | …1110100001010101101 |
3 | 111021020120211112120001 |
4 | 2001100211310022231 |
5 | 4233221001400012 |
6 | 143432033424301 |
7 | 13012241256352 |
oct | 2012045641255 |
9 | 437216745501 |
10 | 138791043757 |
11 | 53951a20453 |
12 | 22a94a0b091 |
13 | 1011b283082 |
14 | 6a08c4a629 |
15 | 3924a17357 |
hex | 20509742ad |
138791043757 has 4 divisors (see below), whose sum is σ = 141744044736. Its totient is φ = 135838042780.
The previous prime is 138791043751. The next prime is 138791043803. The reversal of 138791043757 is 757340197831.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 138791043757 - 23 = 138791043749 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 138791043698 and 138791043707.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (138791043751) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1476500419 + ... + 1476500512.
It is an arithmetic number, because the mean of its divisors is an integer number (35436011184).
Almost surely, 2138791043757 is an apocalyptic number.
It is an amenable number.
138791043757 is a deficient number, since it is larger than the sum of its proper divisors (2953000979).
138791043757 is an equidigital number, since it uses as much as digits as its factorization.
138791043757 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2953000978.
The product of its (nonzero) digits is 4445280, while the sum is 55.
The spelling of 138791043757 in words is "one hundred thirty-eight billion, seven hundred ninety-one million, forty-three thousand, seven hundred fifty-seven".
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