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138802391285771 is a prime number
BaseRepresentation
bin11111100011110101110011…
…001110100000000000001011
3200012110101020022011100000102
4133203311303032200000023
5121143114244132121041
61211112534400000015
741144066436133463
oct3743656316400013
9605411208140012
10138802391285771
1140254844345594
1213698a0000000b
135c5b0176800b5
14263c1005d4ba3
15110a87e70509b
hex7e3d733a000b

138802391285771 has 2 divisors, whose sum is σ = 138802391285772. Its totient is φ = 138802391285770.

The previous prime is 138802391285693. The next prime is 138802391285783. The reversal of 138802391285771 is 177582193208831.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 138802391285771 - 218 = 138802391023627 is a prime.

It is a super-2 number, since 2×1388023912857712 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 138802391285698 and 138802391285707.

It is not a weakly prime, because it can be changed into another prime (138802391285471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69401195642885 + 69401195642886.

It is an arithmetic number, because the mean of its divisors is an integer number (69401195642886).

Almost surely, 2138802391285771 is an apocalyptic number.

138802391285771 is a deficient number, since it is larger than the sum of its proper divisors (1).

138802391285771 is an equidigital number, since it uses as much as digits as its factorization.

138802391285771 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40642560, while the sum is 65.

The spelling of 138802391285771 in words is "one hundred thirty-eight trillion, eight hundred two billion, three hundred ninety-one million, two hundred eighty-five thousand, seven hundred seventy-one".