Base | Representation |
---|---|
bin | 11001110111000100… |
… | …10111001011110101 |
3 | 1022211120202100210210 |
4 | 30323202113023311 |
5 | 211413220443433 |
6 | 10213401140033 |
7 | 1001024026263 |
oct | 147342271365 |
9 | 38746670723 |
10 | 13883765493 |
11 | 5985029564 |
12 | 283578a619 |
13 | 1403502b70 |
14 | 959c9b433 |
15 | 563d23463 |
hex | 33b8972f5 |
13883765493 has 64 divisors (see below), whose sum is σ = 21189754880. Its totient is φ = 8026387200.
The previous prime is 13883765473. The next prime is 13883765501. The reversal of 13883765493 is 39456738831.
It is not a de Polignac number, because 13883765493 - 213 = 13883757301 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13883765473) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5824980 + ... + 5827362.
It is an arithmetic number, because the mean of its divisors is an integer number (331089920).
Almost surely, 213883765493 is an apocalyptic number.
13883765493 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13883765493 is a deficient number, since it is larger than the sum of its proper divisors (7305989387).
13883765493 is a wasteful number, since it uses less digits than its factorization.
13883765493 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2570.
The product of its digits is 13063680, while the sum is 57.
It can be divided in two parts, 13883 and 765493, that added together give a triangular number (779376 = T1248).
The spelling of 13883765493 in words is "thirteen billion, eight hundred eighty-three million, seven hundred sixty-five thousand, four hundred ninety-three".
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