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138851746687481 is a prime number
BaseRepresentation
bin11111100100100011110001…
…000010011010100111111001
3200012122002121222001112000112
4133210203301002122213321
5121144421334122444411
61211151340053314105
741150464503131102
oct3744436102324771
9605562558045015
10138851746687481
1140273771169383
12136a6495035935
135c62881a0a6c9
14264066348d3a9
15110bcbc6bcb8b
hex7e48f109a9f9

138851746687481 has 2 divisors, whose sum is σ = 138851746687482. Its totient is φ = 138851746687480.

The previous prime is 138851746687477. The next prime is 138851746687553. The reversal of 138851746687481 is 184786647158831.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 76267192805881 + 62584553881600 = 8733109^2 + 7911040^2 .

It is an emirp because it is prime and its reverse (184786647158831) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 138851746687481 - 22 = 138851746687477 is a prime.

It is a super-2 number, since 2×1388517466874812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (138851746687081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69425873343740 + 69425873343741.

It is an arithmetic number, because the mean of its divisors is an integer number (69425873343741).

Almost surely, 2138851746687481 is an apocalyptic number.

It is an amenable number.

138851746687481 is a deficient number, since it is larger than the sum of its proper divisors (1).

138851746687481 is an equidigital number, since it uses as much as digits as its factorization.

138851746687481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1734082560, while the sum is 77.

The spelling of 138851746687481 in words is "one hundred thirty-eight trillion, eight hundred fifty-one billion, seven hundred forty-six million, six hundred eighty-seven thousand, four hundred eighty-one".