Base | Representation |
---|---|
bin | 1100101000010000010000… |
… | …1111011111010011011011 |
3 | 1211011110102100010120001012 |
4 | 3022010010033133103123 |
5 | 3310000403302442321 |
6 | 45311000330444135 |
7 | 2632131413164451 |
oct | 312040417372333 |
9 | 54143370116035 |
10 | 13885700437211 |
11 | 447398a9963a9 |
12 | 1683184b9364b |
13 | 799553a5b865 |
14 | 3601002369d1 |
15 | 1912eb60b05b |
hex | ca1043df4db |
13885700437211 has 2 divisors, whose sum is σ = 13885700437212. Its totient is φ = 13885700437210.
The previous prime is 13885700437171. The next prime is 13885700437223. The reversal of 13885700437211 is 11273400758831.
13885700437211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13885700437211 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13885700437211.
It is not a weakly prime, because it can be changed into another prime (13885700437711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6942850218605 + 6942850218606.
It is an arithmetic number, because the mean of its divisors is an integer number (6942850218606).
Almost surely, 213885700437211 is an apocalyptic number.
13885700437211 is a deficient number, since it is larger than the sum of its proper divisors (1).
13885700437211 is an equidigital number, since it uses as much as digits as its factorization.
13885700437211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1128960, while the sum is 50.
The spelling of 13885700437211 in words is "thirteen trillion, eight hundred eighty-five billion, seven hundred million, four hundred thirty-seven thousand, two hundred eleven".
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