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13889670251243 is a prime number
BaseRepresentation
bin1100101000011111000011…
…0111001000001011101011
31211011211200000001000010112
43022013300313020023223
53310032021041014433
645312454301404535
72632331656066343
oct312076067101353
954154600030115
1013889670251243
114475637832446
121683ab256974b
13799a37341747
1436039956dd23
1519147edbc348
hexca1f0dc82eb

13889670251243 has 2 divisors, whose sum is σ = 13889670251244. Its totient is φ = 13889670251242.

The previous prime is 13889670251213. The next prime is 13889670251251. The reversal of 13889670251243 is 34215207698831.

13889670251243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13889670251243 - 28 = 13889670250987 is a prime.

It is not a weakly prime, because it can be changed into another prime (13889670251213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6944835125621 + 6944835125622.

It is an arithmetic number, because the mean of its divisors is an integer number (6944835125622).

It is a 1-persistent number, because it is pandigital, but 2⋅13889670251243 = 27779340502486 is not.

Almost surely, 213889670251243 is an apocalyptic number.

13889670251243 is a deficient number, since it is larger than the sum of its proper divisors (1).

13889670251243 is an equidigital number, since it uses as much as digits as its factorization.

13889670251243 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17418240, while the sum is 59.

The spelling of 13889670251243 in words is "thirteen trillion, eight hundred eighty-nine billion, six hundred seventy million, two hundred fifty-one thousand, two hundred forty-three".