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138909741263 = 233959388517
BaseRepresentation
bin1000000101011110101…
…0100111000011001111
3111021112212011222220222
42001113222213003033
54233441343210023
6143451513501555
713015212214256
oct2012752470317
9437485158828
10138909741263
1153a02a22667
1222b087118bb
1310139a42197
146a1a90779d
153930161cc8
hex2057aa70cf

138909741263 has 4 divisors (see below), whose sum is σ = 138969132120. Its totient is φ = 138850350408.

The previous prime is 138909741239. The next prime is 138909741277. The reversal of 138909741263 is 362147909831.

138909741263 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 138909741263 - 28 = 138909741007 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (138909741203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29691920 + ... + 29696597.

It is an arithmetic number, because the mean of its divisors is an integer number (34742283030).

Almost surely, 2138909741263 is an apocalyptic number.

138909741263 is a deficient number, since it is larger than the sum of its proper divisors (59390857).

138909741263 is an equidigital number, since it uses as much as digits as its factorization.

138909741263 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59390856.

The product of its (nonzero) digits is 1959552, while the sum is 53.

The spelling of 138909741263 in words is "one hundred thirty-eight billion, nine hundred nine million, seven hundred forty-one thousand, two hundred sixty-three".

Divisors: 1 2339 59388517 138909741263