Base | Representation |
---|---|
bin | 1000000101011110101… |
… | …0100111000011001111 |
3 | 111021112212011222220222 |
4 | 2001113222213003033 |
5 | 4233441343210023 |
6 | 143451513501555 |
7 | 13015212214256 |
oct | 2012752470317 |
9 | 437485158828 |
10 | 138909741263 |
11 | 53a02a22667 |
12 | 22b087118bb |
13 | 10139a42197 |
14 | 6a1a90779d |
15 | 3930161cc8 |
hex | 2057aa70cf |
138909741263 has 4 divisors (see below), whose sum is σ = 138969132120. Its totient is φ = 138850350408.
The previous prime is 138909741239. The next prime is 138909741277. The reversal of 138909741263 is 362147909831.
138909741263 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 138909741263 - 28 = 138909741007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (138909741203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29691920 + ... + 29696597.
It is an arithmetic number, because the mean of its divisors is an integer number (34742283030).
Almost surely, 2138909741263 is an apocalyptic number.
138909741263 is a deficient number, since it is larger than the sum of its proper divisors (59390857).
138909741263 is an equidigital number, since it uses as much as digits as its factorization.
138909741263 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 59390856.
The product of its (nonzero) digits is 1959552, while the sum is 53.
The spelling of 138909741263 in words is "one hundred thirty-eight billion, nine hundred nine million, seven hundred forty-one thousand, two hundred sixty-three".
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