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13896447001 is a prime number
BaseRepresentation
bin11001111000100101…
…01111010000011001
31022212110121122120021
430330102233100121
5211424442301001
610214533030441
71001236564513
oct147422572031
938773548507
1013896447001
115991200348
122839a85421
131406023108
1495b83cbb3
15564ecaba1
hex33c4af419

13896447001 has 2 divisors, whose sum is σ = 13896447002. Its totient is φ = 13896447000.

The previous prime is 13896446947. The next prime is 13896447029. The reversal of 13896447001 is 10074469831.

13896447001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11898446400 + 1998000601 = 109080^2 + 44699^2 .

It is an emirp because it is prime and its reverse (10074469831) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13896447001 - 27 = 13896446873 is a prime.

It is a super-2 number, since 2×138964470012 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13896447091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6948223500 + 6948223501.

It is an arithmetic number, because the mean of its divisors is an integer number (6948223501).

Almost surely, 213896447001 is an apocalyptic number.

It is an amenable number.

13896447001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13896447001 is an equidigital number, since it uses as much as digits as its factorization.

13896447001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 145152, while the sum is 43.

The spelling of 13896447001 in words is "thirteen billion, eight hundred ninety-six million, four hundred forty-seven thousand, one".