Base | Representation |
---|---|
bin | 11001111001000100… |
… | …00010100001010011 |
3 | 1022212202011102201021 |
4 | 30330202002201103 |
5 | 211432004124232 |
6 | 10215155020311 |
7 | 1001315641546 |
oct | 147442024123 |
9 | 38782142637 |
10 | 13900458067 |
11 | 599349a981 |
12 | 283b29a697 |
13 | 1406ac8a22 |
14 | 95c1a485d |
15 | 56551e397 |
hex | 33c882853 |
13900458067 has 2 divisors, whose sum is σ = 13900458068. Its totient is φ = 13900458066.
The previous prime is 13900458059. The next prime is 13900458073. The reversal of 13900458067 is 76085400931.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13900458067 - 23 = 13900458059 is a prime.
It is not a weakly prime, because it can be changed into another prime (13900458037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6950229033 + 6950229034.
It is an arithmetic number, because the mean of its divisors is an integer number (6950229034).
Almost surely, 213900458067 is an apocalyptic number.
13900458067 is a deficient number, since it is larger than the sum of its proper divisors (1).
13900458067 is an equidigital number, since it uses as much as digits as its factorization.
13900458067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 181440, while the sum is 43.
Adding to 13900458067 its reverse (76085400931), we get a palindrome (89985858998).
The spelling of 13900458067 in words is "thirteen billion, nine hundred million, four hundred fifty-eight thousand, sixty-seven".
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