Base | Representation |
---|---|
bin | 11111100110111011010111… |
… | …000100100010111011001011 |
3 | 200020012122202220101010221021 |
4 | 133212323113010202323023 |
5 | 121210103214031423103 |
6 | 1211354215550053311 |
7 | 41165316251540050 |
oct | 3746732704427313 |
9 | 606178686333837 |
10 | 139014519795403 |
11 | 403267aa36156a |
12 | 13711b414aa237 |
13 | 5c7502264a095 |
14 | 26484a53c7027 |
15 | 1111147831bbd |
hex | 7e6ed7122ecb |
139014519795403 has 32 divisors (see below), whose sum is σ = 164319719293440. Its totient is φ = 115142091840000.
The previous prime is 139014519795373. The next prime is 139014519795439. The reversal of 139014519795403 is 304597915410931.
It is a cyclic number.
It is not a de Polignac number, because 139014519795403 - 213 = 139014519787211 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (61).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (139014519795443) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 37822003 + ... + 41334403.
It is an arithmetic number, because the mean of its divisors is an integer number (5134991227920).
Almost surely, 2139014519795403 is an apocalyptic number.
139014519795403 is a deficient number, since it is larger than the sum of its proper divisors (25305199498037).
139014519795403 is a wasteful number, since it uses less digits than its factorization.
139014519795403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3514099.
The product of its (nonzero) digits is 18370800, while the sum is 61.
The spelling of 139014519795403 in words is "one hundred thirty-nine trillion, fourteen billion, five hundred nineteen million, seven hundred ninety-five thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •