Base | Representation |
---|---|
bin | 10100001111101110001… |
… | …010100010100011100001 |
3 | 11221000010000021211121211 |
4 | 110033232022202203201 |
5 | 140243310131130433 |
6 | 2543050220150121 |
7 | 202341654245014 |
oct | 24175612424341 |
9 | 4830100254554 |
10 | 1391270176993 |
11 | 497041821034 |
12 | 1a5779698341 |
13 | a1272112128 |
14 | 4b4a304337b |
15 | 262cba508cd |
hex | 143ee2a28e1 |
1391270176993 has 2 divisors, whose sum is σ = 1391270176994. Its totient is φ = 1391270176992.
The previous prime is 1391270176979. The next prime is 1391270177023. The reversal of 1391270176993 is 3996710721931.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 980123760144 + 411146416849 = 990012^2 + 641207^2 .
It is a cyclic number.
It is not a de Polignac number, because 1391270176993 - 233 = 1382680242401 is a prime.
It is not a weakly prime, because it can be changed into another prime (1391270176493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 695635088496 + 695635088497.
It is an arithmetic number, because the mean of its divisors is an integer number (695635088497).
Almost surely, 21391270176993 is an apocalyptic number.
It is an amenable number.
1391270176993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1391270176993 is an equidigital number, since it uses as much as digits as its factorization.
1391270176993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3857868, while the sum is 58.
The spelling of 1391270176993 in words is "one trillion, three hundred ninety-one billion, two hundred seventy million, one hundred seventy-six thousand, nine hundred ninety-three".
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