Base | Representation |
---|---|
bin | 10100010000100011010… |
… | …010010001100100001001 |
3 | 11221002102010021111122021 |
4 | 110100203102101210021 |
5 | 140302121304201001 |
6 | 2543314454124441 |
7 | 202403025425044 |
oct | 24204322214411 |
9 | 4832363244567 |
10 | 1392161397001 |
11 | 4974598a68a1 |
12 | 1a5988050721 |
13 | a138495334b |
14 | 4b549555c5b |
15 | 2632ede5ba1 |
hex | 14423491909 |
1392161397001 has 2 divisors, whose sum is σ = 1392161397002. Its totient is φ = 1392161397000.
The previous prime is 1392161396959. The next prime is 1392161397013. The reversal of 1392161397001 is 1007931612931.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1187064725625 + 205096671376 = 1089525^2 + 452876^2 .
It is a cyclic number.
It is not a de Polignac number, because 1392161397001 - 215 = 1392161364233 is a prime.
It is a super-2 number, since 2×13921613970012 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1392161397091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 696080698500 + 696080698501.
It is an arithmetic number, because the mean of its divisors is an integer number (696080698501).
Almost surely, 21392161397001 is an apocalyptic number.
It is an amenable number.
1392161397001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1392161397001 is an equidigital number, since it uses as much as digits as its factorization.
1392161397001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61236, while the sum is 43.
The spelling of 1392161397001 in words is "one trillion, three hundred ninety-two billion, one hundred sixty-one million, three hundred ninety-seven thousand, one".
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