Base | Representation |
---|---|
bin | 1100101011000001100110… |
… | …1001010011101111100011 |
3 | 1211100000021220221121110010 |
4 | 3022300121221103233203 |
5 | 3311240401331324040 |
6 | 45344512131540003 |
7 | 2635435160211024 |
oct | 312603151235743 |
9 | 54300256847403 |
10 | 13933304167395 |
11 | 4492098a64478 |
12 | 169044b45a603 |
13 | 7a0b9c21a742 |
14 | 3625385d8c4b |
15 | 192685914e80 |
hex | cac19a53be3 |
13933304167395 has 32 divisors (see below), whose sum is σ = 23405275187712. Its totient is φ = 7064397027072.
The previous prime is 13933304167337. The next prime is 13933304167403. The reversal of 13933304167395 is 59376140333931.
It is not a de Polignac number, because 13933304167395 - 222 = 13933299973091 is a prime.
It is a super-2 number, since 2×139333041673952 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 123828394 + ... + 123940863.
It is an arithmetic number, because the mean of its divisors is an integer number (731414849616).
Almost surely, 213933304167395 is an apocalyptic number.
13933304167395 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13933304167395 is a deficient number, since it is larger than the sum of its proper divisors (9471971020317).
13933304167395 is a wasteful number, since it uses less digits than its factorization.
13933304167395 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 247769451.
The product of its (nonzero) digits is 16533720, while the sum is 57.
The spelling of 13933304167395 in words is "thirteen trillion, nine hundred thirty-three billion, three hundred four million, one hundred sixty-seven thousand, three hundred ninety-five".
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