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13942539420841 is a prime number
BaseRepresentation
bin1100101011100100000000…
…0111000000010010101001
31211100220010112201002112001
43022321000013000102221
53311413310042431331
645353040355251001
72636213060445133
oct312710007002251
954326115632461
1013942539420841
114495aa8027039
1216921a82a9a61
137a1a11649255
14362b72d6c053
15192a265b1561
hexcae401c04a9

13942539420841 has 2 divisors, whose sum is σ = 13942539420842. Its totient is φ = 13942539420840.

The previous prime is 13942539420833. The next prime is 13942539420847. The reversal of 13942539420841 is 14802493524931.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8934808483225 + 5007730937616 = 2989115^2 + 2237796^2 .

It is a cyclic number.

It is not a de Polignac number, because 13942539420841 - 23 = 13942539420833 is a prime.

It is not a weakly prime, because it can be changed into another prime (13942539420847) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6971269710420 + 6971269710421.

It is an arithmetic number, because the mean of its divisors is an integer number (6971269710421).

Almost surely, 213942539420841 is an apocalyptic number.

It is an amenable number.

13942539420841 is a deficient number, since it is larger than the sum of its proper divisors (1).

13942539420841 is an equidigital number, since it uses as much as digits as its factorization.

13942539420841 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7464960, while the sum is 55.

The spelling of 13942539420841 in words is "thirteen trillion, nine hundred forty-two billion, five hundred thirty-nine million, four hundred twenty thousand, eight hundred forty-one".