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1394549434913 is a prime number
BaseRepresentation
bin10100010010110001100…
…111111010101000100001
311221022120112210101210212
4110102301213322220201
5140322014123404123
62544351442103505
7202516143420515
oct24226147725041
94838515711725
101394549434913
11498474889048
121a633394ab95
13a167561132b
144b6d4780145
152641e8a7878
hex144b19faa21

1394549434913 has 2 divisors, whose sum is σ = 1394549434914. Its totient is φ = 1394549434912.

The previous prime is 1394549434867. The next prime is 1394549434981. The reversal of 1394549434913 is 3194349454931.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1118701789969 + 275847644944 = 1057687^2 + 525212^2 .

It is an emirp because it is prime and its reverse (3194349454931) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1394549434913 - 210 = 1394549433889 is a prime.

It is not a weakly prime, because it can be changed into another prime (1394549434813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 697274717456 + 697274717457.

It is an arithmetic number, because the mean of its divisors is an integer number (697274717457).

Almost surely, 21394549434913 is an apocalyptic number.

It is an amenable number.

1394549434913 is a deficient number, since it is larger than the sum of its proper divisors (1).

1394549434913 is an equidigital number, since it uses as much as digits as its factorization.

1394549434913 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 25194240, while the sum is 59.

The spelling of 1394549434913 in words is "one trillion, three hundred ninety-four billion, five hundred forty-nine million, four hundred thirty-four thousand, nine hundred thirteen".