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139500433 is a prime number
BaseRepresentation
bin10000101000010…
…01101110010001
3100201111100121201
420110021232101
5241203003213
621501551201
73312506542
oct1024115621
9321440551
10139500433
1171820816
123a875501
1322b93b47
14147544c9
15c3a86dd
hex8509b91

139500433 has 2 divisors, whose sum is σ = 139500434. Its totient is φ = 139500432.

The previous prime is 139500407. The next prime is 139500443. The reversal of 139500433 is 334005931.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88134544 + 51365889 = 9388^2 + 7167^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-139500433 is a prime.

It is not a weakly prime, because it can be changed into another prime (139500443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69750216 + 69750217.

It is an arithmetic number, because the mean of its divisors is an integer number (69750217).

Almost surely, 2139500433 is an apocalyptic number.

It is an amenable number.

139500433 is a deficient number, since it is larger than the sum of its proper divisors (1).

139500433 is an equidigital number, since it uses as much as digits as its factorization.

139500433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4860, while the sum is 28.

The square root of 139500433 is about 11811.0301413552. The cubic root of 139500433 is about 518.6310553633.

The spelling of 139500433 in words is "one hundred thirty-nine million, five hundred thousand, four hundred thirty-three".