Base | Representation |
---|---|
bin | 11001111111001000… |
… | …01110111111101001 |
3 | 1100000021221210000211 |
4 | 30333210032333221 |
5 | 212033022140342 |
6 | 10224214101121 |
7 | 1002504434545 |
oct | 147744167751 |
9 | 40007853024 |
10 | 13951365097 |
11 | 5a0a2000aa |
12 | 285434a7a1 |
13 | 1414510c27 |
14 | 964c56a25 |
15 | 569c27c17 |
hex | 33f90efe9 |
13951365097 has 2 divisors, whose sum is σ = 13951365098. Its totient is φ = 13951365096.
The previous prime is 13951365091. The next prime is 13951365101. The reversal of 13951365097 is 79056315931.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13939108096 + 12257001 = 118064^2 + 3501^2 .
It is an emirp because it is prime and its reverse (79056315931) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13951365097 - 227 = 13817147369 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13951365097.
It is not a weakly prime, because it can be changed into another prime (13951365091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6975682548 + 6975682549.
It is an arithmetic number, because the mean of its divisors is an integer number (6975682549).
Almost surely, 213951365097 is an apocalyptic number.
It is an amenable number.
13951365097 is a deficient number, since it is larger than the sum of its proper divisors (1).
13951365097 is an equidigital number, since it uses as much as digits as its factorization.
13951365097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 765450, while the sum is 49.
The spelling of 13951365097 in words is "thirteen billion, nine hundred fifty-one million, three hundred sixty-five thousand, ninety-seven".
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