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139518127439 = 653213657163
BaseRepresentation
bin1000000111101111101…
…1011010110101001111
3111100010020222012212022
42001323323122311033
54241213120034224
6144032125400355
713036250342015
oct2017373326517
9440106865768
10139518127439
1154195389159
12230584090bb
1310205ab5bc2
146a776348b5
15396878965e
hex207bedad4f

139518127439 has 4 divisors (see below), whose sum is σ = 139731785256. Its totient is φ = 139304469624.

The previous prime is 139518127409. The next prime is 139518127457. The reversal of 139518127439 is 934721815931.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 934721815931 = 1949195885049.

It is a cyclic number.

It is not a de Polignac number, because 139518127439 - 28 = 139518127183 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (139518127409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106827929 + ... + 106829234.

It is an arithmetic number, because the mean of its divisors is an integer number (34932946314).

Almost surely, 2139518127439 is an apocalyptic number.

139518127439 is a deficient number, since it is larger than the sum of its proper divisors (213657817).

139518127439 is an equidigital number, since it uses as much as digits as its factorization.

139518127439 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 213657816.

The product of its digits is 1632960, while the sum is 53.

The spelling of 139518127439 in words is "one hundred thirty-nine billion, five hundred eighteen million, one hundred twenty-seven thousand, four hundred thirty-nine".

Divisors: 1 653 213657163 139518127439