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13955271983 = 65921176437
BaseRepresentation
bin11001111111100110…
…01000110100101111
31100000120022021021022
430333303020310233
5212040022200413
610224433524355
71002552566102
oct147763106457
940016267238
1013955271983
115a11429434
1228557136bb
13141527b2b3
14965592739
1556a24a608
hex33fcc8d2f

13955271983 has 4 divisors (see below), whose sum is σ = 13976449080. Its totient is φ = 13934094888.

The previous prime is 13955271973. The next prime is 13955271989. The reversal of 13955271983 is 38917255931.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 38917255931 = 233316681207.

It is a cyclic number.

It is not a de Polignac number, because 13955271983 - 28 = 13955271727 is a prime.

It is a super-2 number, since 2×139552719832 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13955271989) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10587560 + ... + 10588877.

It is an arithmetic number, because the mean of its divisors is an integer number (3494112270).

Almost surely, 213955271983 is an apocalyptic number.

13955271983 is a deficient number, since it is larger than the sum of its proper divisors (21177097).

13955271983 is an equidigital number, since it uses as much as digits as its factorization.

13955271983 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21177096.

The product of its digits is 2041200, while the sum is 53.

The spelling of 13955271983 in words is "thirteen billion, nine hundred fifty-five million, two hundred seventy-one thousand, nine hundred eighty-three".

Divisors: 1 659 21176437 13955271983