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139571776438561 is a prime number
BaseRepresentation
bin11111101111000010010110…
…001001111100000100100001
3200022011221011002001200211001
4133233002112021330010201
5121243220444232013221
61212502220001552001
741253504506052265
oct3757022611740441
9608157132050731
10139571776438561
1140521070197465
12137a1b41645601
135cb573ca6ab5c
14266744a9c20a5
1511208aee1b391
hex7ef09627c121

139571776438561 has 2 divisors, whose sum is σ = 139571776438562. Its totient is φ = 139571776438560.

The previous prime is 139571776438541. The next prime is 139571776438571. The reversal of 139571776438561 is 165834677175931.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82582020126225 + 56989756312336 = 9087465^2 + 7549156^2 .

It is a cyclic number.

It is not a de Polignac number, because 139571776438561 - 217 = 139571776307489 is a prime.

It is not a weakly prime, because it can be changed into another prime (139571776438541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69785888219280 + 69785888219281.

It is an arithmetic number, because the mean of its divisors is an integer number (69785888219281).

Almost surely, 2139571776438561 is an apocalyptic number.

It is an amenable number.

139571776438561 is a deficient number, since it is larger than the sum of its proper divisors (1).

139571776438561 is an equidigital number, since it uses as much as digits as its factorization.

139571776438561 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 800150400, while the sum is 73.

The spelling of 139571776438561 in words is "one hundred thirty-nine trillion, five hundred seventy-one billion, seven hundred seventy-six million, four hundred thirty-eight thousand, five hundred sixty-one".