Base | Representation |
---|---|
bin | 11001111111110110… |
… | …01111010010111011 |
3 | 1100000201022011101101 |
4 | 30333323033102323 |
5 | 212041043130033 |
6 | 10224551232231 |
7 | 1002606622402 |
oct | 147773172273 |
9 | 40021264341 |
10 | 13957395643 |
11 | 5a12649a24 |
12 | 2856378677 |
13 | 1415842ab9 |
14 | 965986639 |
15 | 56a51997d |
hex | 33fecf4bb |
13957395643 has 2 divisors, whose sum is σ = 13957395644. Its totient is φ = 13957395642.
The previous prime is 13957395629. The next prime is 13957395679. The reversal of 13957395643 is 34659375931.
It is a weak prime.
It is an emirp because it is prime and its reverse (34659375931) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13957395643 - 229 = 13420524731 is a prime.
It is not a weakly prime, because it can be changed into another prime (13957315643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6978697821 + 6978697822.
It is an arithmetic number, because the mean of its divisors is an integer number (6978697822).
Almost surely, 213957395643 is an apocalyptic number.
13957395643 is a deficient number, since it is larger than the sum of its proper divisors (1).
13957395643 is an equidigital number, since it uses as much as digits as its factorization.
13957395643 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9185400, while the sum is 55.
It can be divided in two parts, 13957 and 395643, that added together give a square (409600 = 6402).
The spelling of 13957395643 in words is "thirteen billion, nine hundred fifty-seven million, three hundred ninety-five thousand, six hundred forty-three".
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