Base | Representation |
---|---|
bin | 11001111111110110… |
… | …01111010011000101 |
3 | 1100000201022011101202 |
4 | 30333323033103011 |
5 | 212041043130103 |
6 | 10224551232245 |
7 | 1002606622415 |
oct | 147773172305 |
9 | 40021264352 |
10 | 13957395653 |
11 | 5a12649a33 |
12 | 2856378685 |
13 | 1415842ac6 |
14 | 965986645 |
15 | 56a519988 |
hex | 33fecf4c5 |
13957395653 has 4 divisors (see below), whose sum is σ = 13958510880. Its totient is φ = 13956280428.
The previous prime is 13957395643. The next prime is 13957395679. The reversal of 13957395653 is 35659375931.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35659375931 = 157 ⋅227129783.
It is a cyclic number.
It is not a de Polignac number, because 13957395653 - 212 = 13957391557 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13957395643) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 538625 + ... + 563942.
It is an arithmetic number, because the mean of its divisors is an integer number (3489627720).
Almost surely, 213957395653 is an apocalyptic number.
It is an amenable number.
13957395653 is a deficient number, since it is larger than the sum of its proper divisors (1115227).
13957395653 is a wasteful number, since it uses less digits than its factorization.
13957395653 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1115226.
The product of its digits is 11481750, while the sum is 56.
The spelling of 13957395653 in words is "thirteen billion, nine hundred fifty-seven million, three hundred ninety-five thousand, six hundred fifty-three".
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