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139574088057689 is a prime number
BaseRepresentation
bin11111101111000100011111…
…111100000100001101011001
3200022012011010011210010010022
4133233010133330010031121
5121243240213020321224
61212503241220000225
741253616005355535
oct3757043774041531
9608164104703108
10139574088057689
114052204702409a
12137a2487830075
135cb5a1a95081c
1426675c99d6bc5
151120997d3565e
hex7ef11ff04359

139574088057689 has 2 divisors, whose sum is σ = 139574088057690. Its totient is φ = 139574088057688.

The previous prime is 139574088057587. The next prime is 139574088057697. The reversal of 139574088057689 is 986750880475931.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132547787443600 + 7026300614089 = 11512940^2 + 2650717^2 .

It is an emirp because it is prime and its reverse (986750880475931) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 139574088057689 - 216 = 139574087992153 is a prime.

It is not a weakly prime, because it can be changed into another prime (139574088057389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69787044028844 + 69787044028845.

It is an arithmetic number, because the mean of its divisors is an integer number (69787044028845).

Almost surely, 2139574088057689 is an apocalyptic number.

It is an amenable number.

139574088057689 is a deficient number, since it is larger than the sum of its proper divisors (1).

139574088057689 is an equidigital number, since it uses as much as digits as its factorization.

139574088057689 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3657830400, while the sum is 80.

The spelling of 139574088057689 in words is "one hundred thirty-nine trillion, five hundred seventy-four billion, eighty-eight million, fifty-seven thousand, six hundred eighty-nine".