Base | Representation |
---|---|
bin | 1100101100100100100110… |
… | …1110000100111001110001 |
3 | 1211102112220002001120202122 |
4 | 3023021021232010321301 |
5 | 3312204313403334343 |
6 | 45405025223324025 |
7 | 2640365565433256 |
oct | 313111156047161 |
9 | 54375802046678 |
10 | 13959880527473 |
11 | 44a2396696121 |
12 | 16956278b0615 |
13 | 7a35462008aa |
14 | 36393a08142d |
15 | 1931ddbb7068 |
hex | cb249b84e71 |
13959880527473 has 2 divisors, whose sum is σ = 13959880527474. Its totient is φ = 13959880527472.
The previous prime is 13959880527451. The next prime is 13959880527557. The reversal of 13959880527473 is 37472508895931.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13392913694689 + 566966832784 = 3659633^2 + 752972^2 .
It is a cyclic number.
It is not a de Polignac number, because 13959880527473 - 236 = 13891161050737 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13959880527397 and 13959880527406.
It is not a weakly prime, because it can be changed into another prime (13959880520473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6979940263736 + 6979940263737.
It is an arithmetic number, because the mean of its divisors is an integer number (6979940263737).
Almost surely, 213959880527473 is an apocalyptic number.
It is an amenable number.
13959880527473 is a deficient number, since it is larger than the sum of its proper divisors (1).
13959880527473 is an equidigital number, since it uses as much as digits as its factorization.
13959880527473 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 457228800, while the sum is 71.
The spelling of 13959880527473 in words is "thirteen trillion, nine hundred fifty-nine billion, eight hundred eighty million, five hundred twenty-seven thousand, four hundred seventy-three".
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