Base | Representation |
---|---|
bin | 11111101111100000010110… |
… | …010110010001101111001001 |
3 | 200022022000022020012010000102 |
4 | 133233200112112101233021 |
5 | 121244232433413142003 |
6 | 1212525104415415145 |
7 | 41256025030151303 |
oct | 3757402626215711 |
9 | 608260266163012 |
10 | 139603991927753 |
11 | 405337a1a7a2a1 |
12 | 137a82325244b5 |
13 | 5cb87a51287b2 |
14 | 2668c2537a973 |
15 | 11216482c1588 |
hex | 7ef816591bc9 |
139603991927753 has 2 divisors, whose sum is σ = 139603991927754. Its totient is φ = 139603991927752.
The previous prime is 139603991927681. The next prime is 139603991927767. The reversal of 139603991927753 is 357729199306931.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 132606210537529 + 6997781390224 = 11515477^2 + 2645332^2 .
It is an emirp because it is prime and its reverse (357729199306931) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 139603991927753 - 242 = 135205945416649 is a prime.
It is not a weakly prime, because it can be changed into another prime (139603991957753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69801995963876 + 69801995963877.
It is an arithmetic number, because the mean of its divisors is an integer number (69801995963877).
Almost surely, 2139603991927753 is an apocalyptic number.
It is an amenable number.
139603991927753 is a deficient number, since it is larger than the sum of its proper divisors (1).
139603991927753 is an equidigital number, since it uses as much as digits as its factorization.
139603991927753 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 520812180, while the sum is 74.
The spelling of 139603991927753 in words is "one hundred thirty-nine trillion, six hundred three billion, nine hundred ninety-one million, nine hundred twenty-seven thousand, seven hundred fifty-three".
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