Base | Representation |
---|---|
bin | 10100010100101101100… |
… | …010110111100100000001 |
3 | 11221111221102220011021211 |
4 | 110110231202313210001 |
5 | 140340243343031101 |
6 | 2545334031250121 |
7 | 202621520155231 |
oct | 24245542674401 |
9 | 4844842804254 |
10 | 1396628486401 |
11 | 499341409215 |
12 | 1a6814079941 |
13 | a1917276105 |
14 | 4b850935cc1 |
15 | 264e2182c51 |
hex | 1452d8b7901 |
1396628486401 has 2 divisors, whose sum is σ = 1396628486402. Its totient is φ = 1396628486400.
The previous prime is 1396628486369. The next prime is 1396628486411. The reversal of 1396628486401 is 1046848266931.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 921169970176 + 475458516225 = 959776^2 + 689535^2 .
It is a cyclic number.
It is not a de Polignac number, because 1396628486401 - 25 = 1396628486369 is a prime.
It is a super-2 number, since 2×13966284864012 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1396628486411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 698314243200 + 698314243201.
It is an arithmetic number, because the mean of its divisors is an integer number (698314243201).
Almost surely, 21396628486401 is an apocalyptic number.
It is an amenable number.
1396628486401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1396628486401 is an equidigital number, since it uses as much as digits as its factorization.
1396628486401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11943936, while the sum is 58.
The spelling of 1396628486401 in words is "one trillion, three hundred ninety-six billion, six hundred twenty-eight million, four hundred eighty-six thousand, four hundred one".
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