Base | Representation |
---|---|
bin | 1000001000100110110… |
… | …0100001000001010111 |
3 | 111100201100120220220220 |
4 | 2002021230201001113 |
5 | 4242201232223110 |
6 | 144111100125423 |
7 | 13045053523152 |
oct | 2021154410127 |
9 | 440640526826 |
10 | 139749101655 |
11 | 542a37a7539 |
12 | 23101836873 |
13 | 102418c6737 |
14 | 6a9a19ac99 |
15 | 397dbb1370 |
hex | 2089b21057 |
139749101655 has 16 divisors (see below), whose sum is σ = 223657822080. Its totient is φ = 74513101088.
The previous prime is 139749101651. The next prime is 139749101693. The reversal of 139749101655 is 556101947931.
It is a cyclic number.
It is not a de Polignac number, because 139749101655 - 22 = 139749101651 is a prime.
It is a super-2 number, since 2×1397491016552 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 139749101598 and 139749101607.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (139749101651) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1175997 + ... + 1289366.
It is an arithmetic number, because the mean of its divisors is an integer number (13978613880).
Almost surely, 2139749101655 is an apocalyptic number.
139749101655 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
139749101655 is a deficient number, since it is larger than the sum of its proper divisors (83908720425).
139749101655 is a wasteful number, since it uses less digits than its factorization.
139749101655 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2469150.
The product of its (nonzero) digits is 1020600, while the sum is 51.
The spelling of 139749101655 in words is "one hundred thirty-nine billion, seven hundred forty-nine million, one hundred one thousand, six hundred fifty-five".
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