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139749101651 is a prime number
BaseRepresentation
bin1000001000100110110…
…0100001000001010011
3111100201100120220220202
42002021230201001103
54242201232223101
6144111100125415
713045053523145
oct2021154410123
9440640526822
10139749101651
11542a37a7535
122310183686b
13102418c6733
146a9a19ac95
15397dbb136b
hex2089b21053

139749101651 has 2 divisors, whose sum is σ = 139749101652. Its totient is φ = 139749101650.

The previous prime is 139749101633. The next prime is 139749101693. The reversal of 139749101651 is 156101947931.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 139749101651 - 230 = 138675359827 is a prime.

It is a super-2 number, since 2×1397491016512 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 139749101596 and 139749101605.

It is not a weakly prime, because it can be changed into another prime (139749101351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69874550825 + 69874550826.

It is an arithmetic number, because the mean of its divisors is an integer number (69874550826).

Almost surely, 2139749101651 is an apocalyptic number.

139749101651 is a deficient number, since it is larger than the sum of its proper divisors (1).

139749101651 is an equidigital number, since it uses as much as digits as its factorization.

139749101651 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 204120, while the sum is 47.

The spelling of 139749101651 in words is "one hundred thirty-nine billion, seven hundred forty-nine million, one hundred one thousand, six hundred fifty-one".