Base | Representation |
---|---|
bin | 10100010101100011100… |
… | …010101001111101011111 |
3 | 11221121021120112100121100 |
4 | 110111203202221331133 |
5 | 140344122301302401 |
6 | 2550003552204143 |
7 | 202653130254615 |
oct | 24254342517537 |
9 | 4847246470540 |
10 | 1397534400351 |
11 | 49976680a831 |
12 | 1a6a27539653 |
13 | a1a2cb6057b |
14 | 4b8d8d916b5 |
15 | 2654697bb86 |
hex | 145638a9f5f |
1397534400351 has 24 divisors (see below), whose sum is σ = 2150518509360. Its totient is φ = 871504655616.
The previous prime is 1397534400343. The next prime is 1397534400371. The reversal of 1397534400351 is 1530044357931.
1397534400351 is a `hidden beast` number, since 139 + 75 + 3 + 440 + 0 + 3 + 5 + 1 = 666.
It is not a de Polignac number, because 1397534400351 - 23 = 1397534400343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1397534400297 and 1397534400306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1397534400371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 27994116 + ... + 28043993.
It is an arithmetic number, because the mean of its divisors is an integer number (89604937890).
Almost surely, 21397534400351 is an apocalyptic number.
1397534400351 is a deficient number, since it is larger than the sum of its proper divisors (752984109009).
1397534400351 is a wasteful number, since it uses less digits than its factorization.
1397534400351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56038295 (or 56038292 counting only the distinct ones).
The product of its (nonzero) digits is 680400, while the sum is 45.
The spelling of 1397534400351 in words is "one trillion, three hundred ninety-seven billion, five hundred thirty-four million, four hundred thousand, three hundred fifty-one".
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