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13982404633 is a prime number
BaseRepresentation
bin11010000010110101…
…01001000000011001
31100002110100202021021
431001122221000121
5212113443422013
610231243242441
71003332323041
oct150132510031
940073322237
1013982404633
115a2578060a
122862819421
13141aa8b112
14969016721
1556c809a8d
hex3416a9019

13982404633 has 2 divisors, whose sum is σ = 13982404634. Its totient is φ = 13982404632.

The previous prime is 13982404529. The next prime is 13982404687. The reversal of 13982404633 is 33640428931.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11678692624 + 2303712009 = 108068^2 + 47997^2 .

It is an emirp because it is prime and its reverse (33640428931) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13982404633 - 217 = 13982273561 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13982404633.

It is not a weakly prime, because it can be changed into another prime (13982404693) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6991202316 + 6991202317.

It is an arithmetic number, because the mean of its divisors is an integer number (6991202317).

Almost surely, 213982404633 is an apocalyptic number.

It is an amenable number.

13982404633 is a deficient number, since it is larger than the sum of its proper divisors (1).

13982404633 is an equidigital number, since it uses as much as digits as its factorization.

13982404633 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 373248, while the sum is 43.

The spelling of 13982404633 in words is "thirteen billion, nine hundred eighty-two million, four hundred four thousand, six hundred thirty-three".