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139930051 is a prime number
BaseRepresentation
bin10000101011100…
…10100111000011
3100202022011221111
420111302213003
5241310230201
621515104151
73316246222
oct1025624703
9322264844
10139930051
1171a94578
123aa42057
1322cb4561
1414826cb9
15c440b51
hex85729c3

139930051 has 2 divisors, whose sum is σ = 139930052. Its totient is φ = 139930050.

The previous prime is 139930033. The next prime is 139930057. The reversal of 139930051 is 150039931.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 139930051 - 215 = 139897283 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 139929995 and 139930022.

It is not a weakly prime, because it can be changed into another prime (139930057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69965025 + 69965026.

It is an arithmetic number, because the mean of its divisors is an integer number (69965026).

Almost surely, 2139930051 is an apocalyptic number.

139930051 is a deficient number, since it is larger than the sum of its proper divisors (1).

139930051 is an equidigital number, since it uses as much as digits as its factorization.

139930051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3645, while the sum is 31.

The square root of 139930051 is about 11829.2033121424. The cubic root of 139930051 is about 519.1629172619.

Adding to 139930051 its reverse (150039931), we get a palindrome (289969982).

The spelling of 139930051 in words is "one hundred thirty-nine million, nine hundred thirty thousand, fifty-one".