Base | Representation |
---|---|
bin | 10100010111001111000… |
… | …100011101011101101011 |
3 | 11221202221022010021001101 |
4 | 110113033010131131223 |
5 | 140411321114033141 |
6 | 2550502554502231 |
7 | 203045624231362 |
oct | 24271704353553 |
9 | 4852838107041 |
10 | 1399338424171 |
11 | 49a502072606 |
12 | 1a724b734977 |
13 | a1c5982bc9c |
14 | 4ba2a7d47d9 |
15 | 2660002c531 |
hex | 145cf11d76b |
1399338424171 has 2 divisors, whose sum is σ = 1399338424172. Its totient is φ = 1399338424170.
The previous prime is 1399338424123. The next prime is 1399338424291. The reversal of 1399338424171 is 1714248339931.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1399338424171 - 233 = 1390748489579 is a prime.
It is a super-2 number, since 2×13993384241712 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1399338421171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 699669212085 + 699669212086.
It is an arithmetic number, because the mean of its divisors is an integer number (699669212086).
Almost surely, 21399338424171 is an apocalyptic number.
1399338424171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1399338424171 is an equidigital number, since it uses as much as digits as its factorization.
1399338424171 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3919104, while the sum is 55.
The spelling of 1399338424171 in words is "one trillion, three hundred ninety-nine billion, three hundred thirty-eight million, four hundred twenty-four thousand, one hundred seventy-one".
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