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139935388032001 is a prime number
BaseRepresentation
bin11111110100010100111111…
…000110000101110000000001
3200100110200200210102111010101
4133310110333012011300001
5121320200133314011001
61213341232500202401
741321666236441402
oct3764247706056001
9610420623374111
10139935388032001
11406512a0488391
12138404ba399401
136010b09635983
14267aca21039a9
15112a091e2ea01
hex7f453f185c01

139935388032001 has 2 divisors, whose sum is σ = 139935388032002. Its totient is φ = 139935388032000.

The previous prime is 139935388031981. The next prime is 139935388032019. The reversal of 139935388032001 is 100230883539931.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 137081923823601 + 2853464208400 = 11708199^2 + 1689220^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-139935388032001 is a prime.

It is not a weakly prime, because it can be changed into another prime (139935388032091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69967694016000 + 69967694016001.

It is an arithmetic number, because the mean of its divisors is an integer number (69967694016001).

Almost surely, 2139935388032001 is an apocalyptic number.

It is an amenable number.

139935388032001 is a deficient number, since it is larger than the sum of its proper divisors (1).

139935388032001 is an equidigital number, since it uses as much as digits as its factorization.

139935388032001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4199040, while the sum is 55.

The spelling of 139935388032001 in words is "one hundred thirty-nine trillion, nine hundred thirty-five billion, three hundred eighty-eight million, thirty-two thousand, one".