Base | Representation |
---|---|
bin | 10100010111011001010… |
… | …011110011100001000001 |
3 | 11221210101021101100000001 |
4 | 110113121103303201001 |
5 | 140412144104000232 |
6 | 2550532013000001 |
7 | 203053111403404 |
oct | 24273123634101 |
9 | 4853337340001 |
10 | 1399510218817 |
11 | 49a590040457 |
12 | 1a7299183001 |
13 | a1c862bc119 |
14 | 4ba45553d3b |
15 | 266101646e7 |
hex | 145d94f3841 |
1399510218817 has 2 divisors, whose sum is σ = 1399510218818. Its totient is φ = 1399510218816.
The previous prime is 1399510218793. The next prime is 1399510218889. The reversal of 1399510218817 is 7188120159931.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1367592252481 + 31917966336 = 1169441^2 + 178656^2 .
It is a cyclic number.
It is not a de Polignac number, because 1399510218817 - 215 = 1399510186049 is a prime.
It is not a weakly prime, because it can be changed into another prime (1399510219817) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 699755109408 + 699755109409.
It is an arithmetic number, because the mean of its divisors is an integer number (699755109409).
Almost surely, 21399510218817 is an apocalyptic number.
It is an amenable number.
1399510218817 is a deficient number, since it is larger than the sum of its proper divisors (1).
1399510218817 is an equidigital number, since it uses as much as digits as its factorization.
1399510218817 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1088640, while the sum is 55.
The spelling of 1399510218817 in words is "one trillion, three hundred ninety-nine billion, five hundred ten million, two hundred eighteen thousand, eight hundred seventeen".
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