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13998251487673 is a prime number
BaseRepresentation
bin1100101110110011100011…
…0011101011000110111001
31211120012221012210022202201
43023230320303223012321
53313321404340101143
645434412530230201
72643224502265015
oct313547063530671
954505835708681
1013998251487673
114507697038482
1216a0b56125361
137a704c92047b
1436573a159545
151941d766564d
hexcbb38ceb1b9

13998251487673 has 2 divisors, whose sum is σ = 13998251487674. Its totient is φ = 13998251487672.

The previous prime is 13998251487587. The next prime is 13998251487749. The reversal of 13998251487673 is 37678415289931.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11308477644864 + 2689773842809 = 3362808^2 + 1640053^2 .

It is a cyclic number.

It is not a de Polignac number, because 13998251487673 - 225 = 13998217933241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13998251487596 and 13998251487605.

It is not a weakly prime, because it can be changed into another prime (13998251487973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6999125743836 + 6999125743837.

It is an arithmetic number, because the mean of its divisors is an integer number (6999125743837).

Almost surely, 213998251487673 is an apocalyptic number.

It is an amenable number.

13998251487673 is a deficient number, since it is larger than the sum of its proper divisors (1).

13998251487673 is an equidigital number, since it uses as much as digits as its factorization.

13998251487673 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 548674560, while the sum is 73.

The spelling of 13998251487673 in words is "thirteen trillion, nine hundred ninety-eight billion, two hundred fifty-one million, four hundred eighty-seven thousand, six hundred seventy-three".