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1399978406971 is a prime number
BaseRepresentation
bin10100010111110101001…
…101110011010000111011
311221211120220100202102001
4110113311031303100323
5140414123433010341
62551050255521431
7203100525054424
oct24276515632073
94854526322361
101399978406971
1149a80034a111
121a73a9b29277
13a202c2b6631
144ba8b7c864b
152663b2e6d31
hex145f537343b

1399978406971 has 2 divisors, whose sum is σ = 1399978406972. Its totient is φ = 1399978406970.

The previous prime is 1399978406941. The next prime is 1399978406987. The reversal of 1399978406971 is 1796048799931.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1399978406971 - 215 = 1399978374203 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1399978406894 and 1399978406903.

It is not a weakly prime, because it can be changed into another prime (1399978406941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 699989203485 + 699989203486.

It is an arithmetic number, because the mean of its divisors is an integer number (699989203486).

Almost surely, 21399978406971 is an apocalyptic number.

1399978406971 is a deficient number, since it is larger than the sum of its proper divisors (1).

1399978406971 is an equidigital number, since it uses as much as digits as its factorization.

1399978406971 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 185177664, while the sum is 73.

The spelling of 1399978406971 in words is "one trillion, three hundred ninety-nine billion, nine hundred seventy-eight million, four hundred six thousand, nine hundred seventy-one".