1400000111 has 4 divisors (see below), whose sum is σ = 1404154752. Its totient is φ = 1395845472.

The previous prime is 1400000101. The next prime is 1400000113. The reversal of 1400000111 is 1110000041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1110000041 = 53 ⋅20943397.

It is a cyclic number.

It is not a de Polignac number, because 1400000111 - 2²⁶ = 1332891247 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1400000113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2076815 + ... + 2077488.

It is an arithmetic number, because the mean of its divisors is an integer number (351038688).

Almost surely, 2^1400000111 is an apocalyptic number.

1400000111 is a deficient number, since it is larger than the sum of its proper divisors (4154641).

1400000111 is an equidigital number, since it uses as much as digits as its factorization.

1400000111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4154640.

The product of its (nonzero) digits is 4, while the sum is 8.

The square root of 1400000111 is about 37416.5753510393. The cubic root of 1400000111 is about 1118.6889716467.

Adding to 1400000111 its reverse (1110000041), we get a palindrome (2510000152).

The spelling of 1400000111 in words is "one billion, four hundred million, one hundred eleven", and thus it is an aban number.