1400000133113 has 2 divisors, whose sum is σ = 1400000133114. Its totient is φ = 1400000133112.

The previous prime is 1400000133109. The next prime is 1400000133121. The reversal of 1400000133113 is 3113310000041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1367234426944 + 32765706169 = 1169288^2 + 181013^2 .

It is an emirp because it is prime and its reverse (3113310000041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1400000133113 - 2² = 1400000133109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1400000133091 and 1400000133100.

It is not a weakly prime, because it can be changed into another prime (1400000133193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700000066556 + 700000066557.

It is an arithmetic number, because the mean of its divisors is an integer number (700000066557).

Almost surely, 2^{1400000133113} is an apocalyptic number.

It is an amenable number.

1400000133113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400000133113 is an equidigital number, since it uses as much as digits as its factorization.

1400000133113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1400000133113 its reverse (3113310000041), we get a palindrome (4513310133154).

The spelling of 1400000133113 in words is "one trillion, four hundred billion, one hundred thirty-three thousand, one hundred thirteen".