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14000034221963 is a prime number
BaseRepresentation
bin1100101110111010001100…
…0100010000111110001011
31211120101112110022121110122
43023232203010100332023
53313334032230100323
645435305452333455
72643316620262046
oct313564304207613
954511473277418
1014000034221963
11450842137a0a9
1216a137317428b
137a727507682a
14365868c19c5d
1519428de0cec8
hexcbba3110f8b

14000034221963 has 2 divisors, whose sum is σ = 14000034221964. Its totient is φ = 14000034221962.

The previous prime is 14000034221933. The next prime is 14000034222101. The reversal of 14000034221963 is 36912243000041.

14000034221963 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14000034221963 - 28 = 14000034221707 is a prime.

It is a super-2 number, since 2×140000342219632 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14000034221933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7000017110981 + 7000017110982.

It is an arithmetic number, because the mean of its divisors is an integer number (7000017110982).

Almost surely, 214000034221963 is an apocalyptic number.

14000034221963 is a deficient number, since it is larger than the sum of its proper divisors (1).

14000034221963 is an equidigital number, since it uses as much as digits as its factorization.

14000034221963 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 35.

The spelling of 14000034221963 in words is "fourteen trillion, thirty-four million, two hundred twenty-one thousand, nine hundred sixty-three".