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140004143133 = 346668047711
BaseRepresentation
bin1000001001100011100…
…1011011000000011101
3111101101010111101001120
42002120321123000131
54243212030040013
6144152250401153
713054301403261
oct2023071330035
9441333441046
10140004143133
1154414763a18
12231731301b9
13102826b2a5a
146ac1dca0a1
15399628e123
hex2098e5b01d

140004143133 has 4 divisors (see below), whose sum is σ = 186672190848. Its totient is φ = 93336095420.

The previous prime is 140004143131. The next prime is 140004143137. The reversal of 140004143133 is 331341400041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140004143133 - 21 = 140004143131 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140004143131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23334023853 + ... + 23334023858.

It is an arithmetic number, because the mean of its divisors is an integer number (46668047712).

Almost surely, 2140004143133 is an apocalyptic number.

It is an amenable number.

140004143133 is a deficient number, since it is larger than the sum of its proper divisors (46668047715).

140004143133 is an equidigital number, since it uses as much as digits as its factorization.

140004143133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46668047714.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 140004143133 its reverse (331341400041), we get a palindrome (471345543174).

The spelling of 140004143133 in words is "one hundred forty billion, four million, one hundred forty-three thousand, one hundred thirty-three".

Divisors: 1 3 46668047711 140004143133