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14001152017 is a prime number
BaseRepresentation
bin11010000101000100…
…01010000000010001
31100010202122012211211
431002202022000101
5212133243331032
610233153140121
71003650554116
oct150242120021
940122565754
1014001152017
115a35315816
122868b5a641
131421923348
1496b6d690d
1556e2ae747
hex34288a011

14001152017 has 2 divisors, whose sum is σ = 14001152018. Its totient is φ = 14001152016.

The previous prime is 14001151993. The next prime is 14001152021. The reversal of 14001152017 is 71025110041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13956114496 + 45037521 = 118136^2 + 6711^2 .

It is an emirp because it is prime and its reverse (71025110041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14001152017 is a prime.

It is not a weakly prime, because it can be changed into another prime (14001152047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7000576008 + 7000576009.

It is an arithmetic number, because the mean of its divisors is an integer number (7000576009).

Almost surely, 214001152017 is an apocalyptic number.

It is an amenable number.

14001152017 is a deficient number, since it is larger than the sum of its proper divisors (1).

14001152017 is an equidigital number, since it uses as much as digits as its factorization.

14001152017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 280, while the sum is 22.

Adding to 14001152017 its reverse (71025110041), we get a palindrome (85026262058).

The spelling of 14001152017 in words is "fourteen billion, one million, one hundred fifty-two thousand, seventeen".