14001200001301 has 4 divisors (see below), whose sum is σ = 14001264739072. Its totient is φ = 14001135263532.

The previous prime is 14001200001263. The next prime is 14001200001403. The reversal of 14001200001301 is 10310000210041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14001200001301 is a prime.

It is a super-2 number, since 2×14001200001301² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14001200001101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32043381 + ... + 32477386.

It is an arithmetic number, because the mean of its divisors is an integer number (3500316184768).

Almost surely, 2^{14001200001301} is an apocalyptic number.

It is an amenable number.

14001200001301 is a deficient number, since it is larger than the sum of its proper divisors (64737771).

14001200001301 is an equidigital number, since it uses as much as digits as its factorization.

14001200001301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64737770.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 14001200001301 its reverse (10310000210041), we get a palindrome (24311200211342).

The spelling of 14001200001301 in words is "fourteen trillion, one billion, two hundred million, one thousand, three hundred one".