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14001212200111 = 19736905905269
BaseRepresentation
bin1100101110111110100101…
…0001111001010010101111
31211120111120112220002200221
43023233221101321102233
53313343440310400421
645440022412432211
72643361043030503
oct313575121712257
954514515802627
1014001212200111
114508976304564
1216a1641778667
137a740212a516
1436593b456303
1519430c548841
hexcbbe94794af

14001212200111 has 4 divisors (see below), whose sum is σ = 14738118105400. Its totient is φ = 13264306294824.

The previous prime is 14001212200093. The next prime is 14001212200139. The reversal of 14001212200111 is 11100221210041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14001212200111 - 29 = 14001212199599 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14001212230111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 368452952616 + ... + 368452952653.

It is an arithmetic number, because the mean of its divisors is an integer number (3684529526350).

Almost surely, 214001212200111 is an apocalyptic number.

14001212200111 is a deficient number, since it is larger than the sum of its proper divisors (736905905289).

14001212200111 is an equidigital number, since it uses as much as digits as its factorization.

14001212200111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 736905905288.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 14001212200111 its reverse (11100221210041), we get a palindrome (25101433410152).

The spelling of 14001212200111 in words is "fourteen trillion, one billion, two hundred twelve million, two hundred thousand, one hundred eleven".

Divisors: 1 19 736905905269 14001212200111