14001212333441 has 2 divisors, whose sum is σ = 14001212333442. Its totient is φ = 14001212333440.

The previous prime is 14001212333431. The next prime is 14001212333473. The reversal of 14001212333441 is 14433321210041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9276258033025 + 4724954300416 = 3045695^2 + 2173696^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14001212333441 is a prime.

It is a super-2 number, since 2×14001212333441² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14001212333411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7000606166720 + 7000606166721.

It is an arithmetic number, because the mean of its divisors is an integer number (7000606166721).

Almost surely, 2^{14001212333441} is an apocalyptic number.

It is an amenable number.

14001212333441 is a deficient number, since it is larger than the sum of its proper divisors (1).

14001212333441 is an equidigital number, since it uses as much as digits as its factorization.

14001212333441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 14001212333441 its reverse (14433321210041), we get a palindrome (28434533543482).

The spelling of 14001212333441 in words is "fourteen trillion, one billion, two hundred twelve million, three hundred thirty-three thousand, four hundred forty-one".