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1400121654613 = 11127283786783
BaseRepresentation
bin10100010111111101110…
…000001111110101010101
311221211221212220111020021
4110113331300033311111
5140414422120421423
62551112414105141
7203104214462143
oct24277560176525
94854855814207
101400121654613
1149a87419a1a0
121a7429aab1b1
13a2052b8cc56
144baa2836593
1526648b9095d
hex145fdc0fd55

1400121654613 has 4 divisors (see below), whose sum is σ = 1527405441408. Its totient is φ = 1272837867820.

The previous prime is 1400121654611. The next prime is 1400121654649. The reversal of 1400121654613 is 3164561210041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1400121654613 - 21 = 1400121654611 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1400121654611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63641893381 + ... + 63641893402.

It is an arithmetic number, because the mean of its divisors is an integer number (381851360352).

Almost surely, 21400121654613 is an apocalyptic number.

It is an amenable number.

1400121654613 is a deficient number, since it is larger than the sum of its proper divisors (127283786795).

1400121654613 is a wasteful number, since it uses less digits than its factorization.

1400121654613 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 127283786794.

The product of its (nonzero) digits is 17280, while the sum is 34.

Adding to 1400121654613 its reverse (3164561210041), we get a palindrome (4564682864654).

The spelling of 1400121654613 in words is "one trillion, four hundred billion, one hundred twenty-one million, six hundred fifty-four thousand, six hundred thirteen".

Divisors: 1 11 127283786783 1400121654613