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14001250345 = 523121750003
BaseRepresentation
bin11010000101000101…
…00010000000101001
31100010202211012201121
431002202202000221
5212133310002340
610233155215241
71003651443565
oct150242420051
940122735647
1014001250345
115a35382685
122868ba7521
131421959024
1496b7206a5
1556e2cd94a
hex3428a2029

14001250345 has 8 divisors (see below), whose sum is σ = 17532000576. Its totient is φ = 10714000176.

The previous prime is 14001250313. The next prime is 14001250363. The reversal of 14001250345 is 54305210041.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14001250345 - 25 = 14001250313 is a prime.

It is a super-2 number, since 2×140012503452 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60874887 + ... + 60875116.

It is an arithmetic number, because the mean of its divisors is an integer number (2191500072).

Almost surely, 214001250345 is an apocalyptic number.

It is an amenable number.

14001250345 is a deficient number, since it is larger than the sum of its proper divisors (3530750231).

14001250345 is a wasteful number, since it uses less digits than its factorization.

14001250345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121750031.

The product of its (nonzero) digits is 2400, while the sum is 25.

Adding to 14001250345 its reverse (54305210041), we get a palindrome (68306460386).

The spelling of 14001250345 in words is "fourteen billion, one million, two hundred fifty thousand, three hundred forty-five".

Divisors: 1 5 23 115 121750003 608750015 2800250069 14001250345