Base | Representation |
---|---|
bin | 1000001001100101101… |
… | …1101010111110011001 |
3 | 111101101202101111222012 |
4 | 2002121123222332121 |
5 | 4243221324341213 |
6 | 144153211035305 |
7 | 13054440616133 |
oct | 2023133527631 |
9 | 441352344865 |
10 | 140013121433 |
11 | 544198364a9 |
12 | 2317613bb35 |
13 | 10284507563 |
14 | 6ac3286053 |
15 | 3996e644a8 |
hex | 20996eaf99 |
140013121433 has 2 divisors, whose sum is σ = 140013121434. Its totient is φ = 140013121432.
The previous prime is 140013121363. The next prime is 140013121441. The reversal of 140013121433 is 334121310041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 97911416464 + 42101704969 = 312908^2 + 205187^2 .
It is a cyclic number.
It is not a de Polignac number, because 140013121433 - 28 = 140013121177 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 140013121399 and 140013121408.
It is not a weakly prime, because it can be changed into another prime (140013171433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70006560716 + 70006560717.
It is an arithmetic number, because the mean of its divisors is an integer number (70006560717).
Almost surely, 2140013121433 is an apocalyptic number.
It is an amenable number.
140013121433 is a deficient number, since it is larger than the sum of its proper divisors (1).
140013121433 is an equidigital number, since it uses as much as digits as its factorization.
140013121433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 140013121433 its reverse (334121310041), we get a palindrome (474134431474).
The spelling of 140013121433 in words is "one hundred forty billion, thirteen million, one hundred twenty-one thousand, four hundred thirty-three".
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