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140013202014401 is a prime number
BaseRepresentation
bin11111110101011101011101…
…001010111000000011000001
3200100202010112210011100201112
4133311131131022320003001
5121322434014203430101
61213441102124013105
741330422445411012
oct3765353512700301
9610663483140645
10140013202014401
11406812a1445051
12138535b6091195
13601825a8c3541
142680964801009
15112c0e85446bb
hex7f575d2b80c1

140013202014401 has 2 divisors, whose sum is σ = 140013202014402. Its totient is φ = 140013202014400.

The previous prime is 140013202014391. The next prime is 140013202014449. The reversal of 140013202014401 is 104410202310041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 126204553446400 + 13808648568001 = 11234080^2 + 3715999^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140013202014401 is a prime.

It is a super-2 number, since 2×1400132020144012 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (140013202010401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70006601007200 + 70006601007201.

It is an arithmetic number, because the mean of its divisors is an integer number (70006601007201).

Almost surely, 2140013202014401 is an apocalyptic number.

It is an amenable number.

140013202014401 is a deficient number, since it is larger than the sum of its proper divisors (1).

140013202014401 is an equidigital number, since it uses as much as digits as its factorization.

140013202014401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 140013202014401 its reverse (104410202310041), we get a palindrome (244423404324442).

The spelling of 140013202014401 in words is "one hundred forty trillion, thirteen billion, two hundred two million, fourteen thousand, four hundred one".